The mean of three numbers x,y,z us 6 and the mean of five numbers x,y,z,a,b is 8.find the mean of a and b
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Answered by
2
mean of x, y, z = (x+y+z)/3=6(given)
so, x+y+z=18
mean of x, y, z, a,b=(x+y+z+a+b)/5=8(given)
so, x+y+z+a+b=40
a+b=40-18=22
mean of a and b =11
so, x+y+z=18
mean of x, y, z, a,b=(x+y+z+a+b)/5=8(given)
so, x+y+z+a+b=40
a+b=40-18=22
mean of a and b =11
Answered by
0
mean of x, y, z =6
total numbers = 3
average = sum of all observations / no of observations
6 = sum / 3
6 * 3 = sum
18 = x + y + z
x + y + z+ a + b can be written as 18 + a + b
no of observations = 5
8 = 18 + a + b / 6
6 * 8 = 18 + a + b
48 - 18 = a + b
30 = a + b
no = 2
sum / no = average
30 / 2 = avg
15 = average
total numbers = 3
average = sum of all observations / no of observations
6 = sum / 3
6 * 3 = sum
18 = x + y + z
x + y + z+ a + b can be written as 18 + a + b
no of observations = 5
8 = 18 + a + b / 6
6 * 8 = 18 + a + b
48 - 18 = a + b
30 = a + b
no = 2
sum / no = average
30 / 2 = avg
15 = average
Sidnair1:
calculation mistake in my answer
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