The mean of x1,x2 is 6 mean of x1,x2,x3 is 7.Find the value of x3.
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Answered by
64
Hi friend!!
The mean of x₁ and x₂ is 6
⇒(x₁+x₂)/2 = 6
⇒x₁+x₂ = 12
The mean of x₁,x₂ and x₃ is 7
⇒(x₁+x₂+x₃)/3 = 7
⇒ (12+x₃) = 21
⇒ x₃ = 21-12
⇒ x₃ = 9
The value of x₃ is 9
The mean of x₁ and x₂ is 6
⇒(x₁+x₂)/2 = 6
⇒x₁+x₂ = 12
The mean of x₁,x₂ and x₃ is 7
⇒(x₁+x₂+x₃)/3 = 7
⇒ (12+x₃) = 21
⇒ x₃ = 21-12
⇒ x₃ = 9
The value of x₃ is 9
gujjar4:
Thnx bro
Answered by
29
Hello my friend...here is the solution of ur question.
First I should clear u what is mean...mean is =sum of observation ÷ no.of observations.OK friend
Now.Mean of x1 and x2=6
So...it means that
(x1 +x2)÷2=6
So,x1+x2=6×2
x1+x2=12.
Now,
(x1+x2+x3)÷3=7
So,12+x3=7×3
So x3=21-12
x3 = 9
.hope it helped .plz mark as brainliest..thanku good day
First I should clear u what is mean...mean is =sum of observation ÷ no.of observations.OK friend
Now.Mean of x1 and x2=6
So...it means that
(x1 +x2)÷2=6
So,x1+x2=6×2
x1+x2=12.
Now,
(x1+x2+x3)÷3=7
So,12+x3=7×3
So x3=21-12
x3 = 9
.hope it helped .plz mark as brainliest..thanku good day
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