the mean of100observation is60.if one observation of50 is replaced by110,then what will be the new mean
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total no. of observation = 100
mean of no. of observation = 60
mean of no. of observation = 60
jasmeen4:
i dont understand
plsss
total no. of observation = 100
mean of no. of observation = 60
therefore, total sum of obs. = 60 X 100 = 6000
if one is replaced from 50 to 110 then,
total no. of obs - replaced no. = 6000 - 50 = 5950 (new sum of mean)
now, add replaced no. by new sum of mean i.e., 5950 + 110 = 6060 (new sum of new obs)
now, divide new sum by total no. of mean ie., 6060/60 = 101
hope this helps
mean of no. of observation = 60
therefore, total sum of obs. = 60 X 100 = 6000
if one is replaced from 50 to 110 then,
total no. of obs - replaced no. = 6000 - 50 = 5950 (new sum of mean)
now, add replaced no. by new sum of mean i.e., 5950 + 110 = 6060 (new sum of new obs)
now, divide new sum by total no. of mean ie., 6060/60 = 101
hope this helps
Dis is total ans
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Mean=sum of all observation /no of observation
60=sum of all observation /100
Sum of all observation =6000
Now 50is replaced by 110
So, here sum of all observation =6000+110-50
=5940
New mean=6060/100
=hence your new mean be 60.6 ans
Raju kumar
60=sum of all observation /100
Sum of all observation =6000
Now 50is replaced by 110
So, here sum of all observation =6000+110-50
=5940
New mean=6060/100
=hence your new mean be 60.6 ans
Raju kumar
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