The mean proportion between two numbers is 12. The third proportion of the same numbers is 96. Find the greater of the two numbers?
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Let the required no. be a and b.
Therefore,14 is the mean proportional between a and b.
a:14=14:b
ab= 196. eqn....1
and, 112 is third proportional to a and b
a:b=b:112
b square=112 a. eqn....2
From eqn.1;. ab=196.
a=196/b
substituting a =196/b in eqn ...2, we get:
b square= 112*196/b
b cube=112*196 and, b = 28
therefore. a=196/b
196/28. = 7
therefore the required numbers are 28 and 7
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