Math, asked by sayyedvasim834, 10 months ago

The mean salary of 20 workers is Rs.10.250. If the salary of office superintendent
bied, the mean will increase by Rs.750. Find the salary of the office superintende​

Answers

Answered by Sharad001
381

Question :-

The mean salary of 20 workers is Rs.10,250. If the salary of office superintendent bied, the mean will increase by Rs.750. Find the salary of the office superintende .

Answer :-

Salary of office superintendent is ₹26,000

To Find :-

→ Salary of the office supernitende .

Solution :-

Given that :

  • Mean salary =₹ 10,250

  • Total number of workers = 20

  • mean increased =₹ 750

Now ,

we know that ,

 \to \sf \: mean \:  \frac{sum \: of \: observations}{number \: of \: observations}  \\  \\  \to  \sf sum \: of \: obs. = mean \times no. \: of \: obs. \\  \\  \to \sf \: sum \: of \: observations = 10250 \times 20 \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   = 205000

now ,salary of office superintendent is added hence ,

  • Number of observations = 21

  • Let, the salary of office superintendent is "y" .

now, according to the question,

→ salary increased by ₹750 ,

hence ,

 \to \sf 10250 + 750 =  \frac{sum \: of \: observations}{21}  \\  \\  \to \sf 11000 =  \frac{205000 + y}{21}  \\  \\  \to \sf \: y + 205000 = 21 \times 11000 \\  \\  \to \sf y = 231000 - 205000 \\  \\  \to  \boxed{\sf \: y =2 6000}

hence ,salary of office superintendent is ₹26,000


Anonymous: Awesome
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Answered by EliteSoul
260

Answer:

\small\bold\red{Salary \:  } = \huge{\boxed{\mathfrak\green{Rs.26,000}}}

Step-by-step explanation:

Let salary of office superintendent be X

Given:-

  • Mean salary of 20 workers = Rs.10,250
  • If salary of office superintendent is added, mean will increase by Rs.750

  • Salary of superintendent = ?

{\boxed{\bold{Mean =\dfrac{Sum\:of\:salaries}{Number\:of\:workers} }}}

\Rightarrow\sf 10250 =\dfrac{Sum\:of\:salaries}{20} \\\\\Rightarrow\sf Sum\:of\:salaries = 10250 \times 20 \\\\\Rightarrow{\boxed{\bold\red{Sum\:of\:salaries = Rs.205,000 }}}

\rule{300}{1}

Now according to question :-

  • Number of workers = 21
  • Mean increases = Rs.750
  • Salary of the office superintendent=?

\Rightarrow\sf (10250 + 750)<strong> </strong>= \dfrac{205,000 + X }{21} \\\\\Rightarrow\sf 11,000 =\dfrac{205,000 + X}{21} \\\\\Rightarrow\sf 205,000 + X = 11,000 \times 21 \\\\\Rightarrow\sf 205,000 + X = 231,000 \\\\\Rightarrow\sf X = Rs.(231,000 - 205,000) \\\\\Rightarrow\huge{\boxed{\mathfrak\green{X = Rs.26,000 }}}

\therefore\bold{\underline{Salary\:of\:office\:superintendent = Rs.26,000 }}


Anonymous: Splendid!!
kaushik05: perfect
Arcel: Well Explained !
Anonymous: Awesome
Sauron: Mesmerizingggg ! ~_~
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