The Mean wage of 100 labourers working in a factory, running in two shifts
of 60 and 40 labourers respectively 38. The mean wage of 60 labourers
working in first shift is 40. Find the mean wage of 40 labourers working
in the second shift.
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Answer:
Let the total wages of laborers working in shift 1 is x
Let the total wages of laborers working in shift 2 is y
Let the total wages of laborers working in shift 3 is z
Mean wages of 150 laborers =
a+b+c
x+y+z
Where a, b and c is the number of laborers working is shift 1,2 and 3 respt
Mean wages =114 Rs
∴
150
x+y+z
=114⇒x+y+z=114×150=17100
Mean wages of laborers in shift 1 is=
a
x
=121.5⇒x=121.5×60=7290 ( a=60)
Mean wages of laborers in shift 2 is=
b
y
=107.75⇒x=107.75×40=4310 ( a=40)
(x+y+z)=17100
Or 7290+4310+z=17100 Or z=17100-7290-4310=5500
Let the mean of laborers in shift 3=c
∴m=
c
z
=
50
5500
=110 Rs
Then mean wage of laborer working in third shift=Rs 110
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