The mean weight of a group of 7 students is 54kg the individual weights in kg of 5 of them are 61,58,48,52, and 57 if the weight of one of the two remaining students be 6kg more than that of the other find the individual weight of those two boys
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Let weight of other two be (x+6) and x kg respectively.
Mean weight = Sum of weight of all students/ Total no of students
> 54 = (61+58+48+52+57+x+6+x)/7
> 378 = 282+ 2x
> 2x = 96
> x = 48
So, weight of other two will be, (x +6) = 54 kg and 48 kg.
Mean weight = Sum of weight of all students/ Total no of students
> 54 = (61+58+48+52+57+x+6+x)/7
> 378 = 282+ 2x
> 2x = 96
> x = 48
So, weight of other two will be, (x +6) = 54 kg and 48 kg.
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