Question

The measure of 3 angles of a triangle are(y+10)°; (2y-70)° and y°, the least of the 3 angles is___ *​

Answer 1

Firstly start with the sum of all the angles in a triangle that is 180°
So,
Y+10+2y-70+y=180°
4y-60=180°
4y=180°+60°(you can add another step here by writing transporting)
4y=240°
Y=240°/4°
Y=60°
Hope it helps you

Answer 2

$(y + 10) + (2y - 70) + y = 180 \\ \\ (y + 2y + y) + (10 - 70) = 180 \\ \\ 4y - 60 = 180 \\ \\ 4y = 180 + 60 \\ \\ 4y = 240 \\ \\ y = \frac{240}{4} \\ \\ y = 60 \: degree \\ \\ 1st \: angle = y + 10 = 60 + 10 = 70 \: degree \\ \\ 2nd \: angle = 2y - 70 = 2 \times 60 - 70 = 120 - 70 = 50 \: degree \\ \\ 3rd \: angle = y = 60 \: degree \\ \\ so \: the \: least \: angle \: is \: 2nd \: angle = 50 \: degree$

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