Math, asked by yaravavasudha26, 6 months ago

The measure of a sector angle is 90 degree and its diameter is 2 Cm. What is the area of its minor segment(in form of π?

(a)(π-2)/4

( b) (π+2)/4

(c) (π-2)/2

(d) none of these

Answers

Answered by priya2806
24

Answer:

i think b)

mark it as brainlist answer

Answered by Anonymous
3

The measure of a sector angle is 90 degree and its diameter is 2 Cm. What is the area of its minor segment(in form of π?

(a)(π-2)/4 ______correct option(a)

( b) (π+2)/4

(c) (π-2)/2

(d) none of these

Explanation:-

⠀⠀

 \\ \large\sf  \blue{\star Given \: that : :   \longmapsto} \\

\sf \bullet\theta = 90 ^{0}  \\ \\  \sf \bullet Diameter = 2cm \\ \\ \sf \implies radius (r) =  \dfrac{2}{2}  = 1cm

⠀⠀

•Now we know that , Area of segment

 \\  \sf \implies   \dfrac{ \theta^{0} }{360^{0} }  \pi {r}^{2}  -\dfrac{1}{2}  {r}^{2}  sin \theta \\

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Now putting all given values in it

 \implies \sf \dfrac{90^{0} }{360^{0} }  \pi \times 1 \times 1 -  \dfrac{1}{2}  \times1 \times 1  \times 1

 \implies \sf \dfrac{1}{4}  \pi  -  \dfrac{1}{2}

\large\boxed{\boxed{ \red{ \implies \sf \dfrac{  \pi - 2}{4} }}} \\

⠀⠀

So the correct option is (a)

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