Question

the measure of a triangle is 3a+7b-8 if the measure of two sides is 6a+8b-7c and a-3b-2c find the measure of third side

Answer 1

Answer:

-4a+12b-8-5c

Step-by-step explanation:

let 3rd side = x

(6a+8b-7c) + (a-3b-2c) + x = 3a+7b-8

7a+5b-5c + x = 3a+7b-8

x = (3a+7b-8) - (7a+5b-5c)

x = (3a-7a) + (7b+5b) + (-8) + (-5c)

x = -4a+12b-8-5c

Please thank me and mark me as brainliest