THE MEASURE OF ADJECENT ANGLES OF PARALLELOGRAM ARE IN RATIO 3:2 FIND THE MEASURE OF EACH OF THE ANGLE OF THE PARALLELOGRAM
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Let the angles be 3x and 2x.
Sum of all four angles: 10x (3x+2x+3x+2x)
Since the sum of all angles of a parallelogram is 360, therefore: 360/10 = x
i.e. x = 36.
Hence, angles will be, 108 (3x), 72(2x), 108(3x), 72(2x).
Sum of all four angles: 10x (3x+2x+3x+2x)
Since the sum of all angles of a parallelogram is 360, therefore: 360/10 = x
i.e. x = 36.
Hence, angles will be, 108 (3x), 72(2x), 108(3x), 72(2x).
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let the angles be 3x and 2x
3x+2x=180° ( the sum of co-interior angles on the same side of a transversal is 180°)
x=180°/5
x=36°
angles of ||GM are 108° and 72°
3x+2x=180° ( the sum of co-interior angles on the same side of a transversal is 180°)
x=180°/5
x=36°
angles of ||GM are 108° and 72°
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