Math, asked by yashee55, 8 months ago

The measure of all the angels of a
I parallelogram, is an angle is 24 less than turce
the smallest angle, and respectively​

Answers

Answered by hencyboy2003
0

Answer:

Let the smallest angle be x .

Then the other angle will be 2x - 24..

Now,

x+ x+2x-24+2x- 24=360. (:angle sum property of of a parallelogram)

6x - 48 =360

6x=360+48

6x=408

x=408/6

x=68

So the smallest angle is 68 degree.

and, 2x -24=2*68-24=112

So,

The angles of the parallelogram are 68 degree, 112 degree, 68 degree and 112 degree respectively..

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