Question

THE MEASURE OF AN AGALE MADE BYA TRANSVERAL TO TWO PARALLEAL LINES IS 40DEGREES.WHAT IS THE MEASURE OF ITS CORRESPONDINGS ANGLES

Answer 1

Answer:

$\red{\underline{Question:-}}$

THE MEASURE OF ANGLE MADE BY A TRANSVERSAL TO TWO PARALLEL LINES IS 40 DEGREES.WHAT IS THE MEASURE OF ITS CORRESPONDING ANGLES?

$\red{\underline{Solution:-}}$

If a transversal intersects two Parallel Lines ,

if the measure of one of the angle is 40 degree

then to find the measure of its corresponding  angle

As we know that < ELB = < ALM [ vertically opposite angles]

< ELB = < ALM = 40°

< ELB = < LMD [ corresponding angles]

< ELB = < LMD = 40°

< LMD = < CMF [ vertically opposite angles]

< LMD = < CMF = 40°

< BLM + < LMD = 180°

<BLM = 140°

<BLM = 140° = <DMF [ corresponding angles]

<DMF = 140° = <CML [ vertically opposite angles]

<BLM = 140° = <ALE[ vertically opposite angles]

Thus one can calculate all the angles of transversal intersects two Parallel Lines,if one of the angle is given.