Question

The measure of an angle is 4/5 th of that of its complement. Find the degree measure of the angle and that of its supplement.what are the derivation of motion class 9

Answer 1

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Khushi020

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Let the supplement angle be x

Then, angle be (4/5) of x =4x/5

ATQ,

x+4x/5 = 180°

(5x+4x)/5 = 180°

9x = 180×5

x=(180×5)/9

x=100°

Then,

x=100°

4x/5 =(4×100)/5 =400/5 =80°

Thus,

angles are 80° & 100°

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Answer 2

Let the supplement angle be x

Then, angle be (4/5) of x =4x/5

ATQ,x+4x/5 = 180°(5x+4x)/5 =18p° 9x= 180* 5x= (=(180×5)/9x=100°

Then,x=100°4x/5 =(4×100)/5 =400/5 =80°

Thus,angles are 80° & 100°

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