Math, asked by priyabansal176, 3 months ago

The measure of angle A and Angle B of an isosceles triangle ABC and equal angle ACD is the external angle of triangle ABC the measure of angle ACB and ac angle are bracket 3 x minus 24 (The greeks and) 7 x + 4 degree respectively find the measure of angle ACB and angle ACD also find the measure of angle A and Angle B

Answers

Answered by ʍɨֆֆƈʊȶɨɛ
3

Answer:

ACB+ACD = 180° .......... Linear Pair

→3x 17+ 8x + 10 = 180°

→ 11x7 = 180

11x 187

X = 17

mZACB (3x-17) = (3 x 17-17) = 34° mZACD (8x + 10)° (8 x 17+ 10)° 146°

mZACD = mZA+mZB (Property of exterior angle of a triangle) →mZACD 2(mZA) (ZA = ZB) →mZA 1462=73° = m/B

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