The measure of angle A and Angle B of an isosceles triangle ABC and equal angle ACD is the external angle of triangle ABC the measure of angle ACB and ac angle are bracket 3 x minus 24 (The greeks and) 7 x + 4 degree respectively find the measure of angle ACB and angle ACD also find the measure of angle A and Angle B
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ACB+ACD = 180° .......... Linear Pair
→3x 17+ 8x + 10 = 180°
→ 11x7 = 180
11x 187
X = 17
mZACB (3x-17) = (3 x 17-17) = 34° mZACD (8x + 10)° (8 x 17+ 10)° 146°
mZACD = mZA+mZB (Property of exterior angle of a triangle) →mZACD 2(mZA) (ZA = ZB) →mZA 1462=73° = m/B
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