Question

the measure of angle C in trapezium ABCD given that sides AB and DC are parallel.And angle B=112 degree

Answer 1

Angle C will measure 68 degree

Answer 2

Answer:

According to the information provided the trapezium may look something like this.

∠A=∠B=45°

lets draw two lines ⏊ on line AB. Lets name there point of intersection as P and Q from left to right.

∠P = 90°

∴ ∠APD+∠PDA+∠DAP = 180° (Angel sum property)

= 90° + ∠PDA +45° = 180

= ∠PDA = 45°

∵ ∠PDC +∠PDA = ∠ADC

= 45°+90° =∠ADC

=135° = ∠ADC

∠C = ∠D (∵ There are correspondive by virtue)

∴ ∠C and ∠D equal to 135°

hope it helps