the measure of angle of a Pentagon are ( x-5)° , ( x-6)° , ( 2x-7)° , x° and (2x - 2)°
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Answered by
4
X-5 + x-6 + 2x-7 + x + 2x-2 = 540
7x=560
X=80
7x=560
X=80
Answered by
5
Since, sum of all interior angles of pentagon is 540
So,
( x-5)° + ( x-6)° + ( 2x-7)° + x° + (2x - 2)° = 540°
(7x - 5 - 6 - 7 - 2)° =540°
(7x - 20)° =540°
7x =540° + 20°
7x =560°
x = 80°
So,
( x-5)° + ( x-6)° + ( 2x-7)° + x° + (2x - 2)° = 540°
(7x - 5 - 6 - 7 - 2)° =540°
(7x - 20)° =540°
7x =540° + 20°
7x =560°
x = 80°
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