the measure of angle of a Pentagon are (x- 5)° , (x-6 )° , (2x-7)° , x° and (2x - 2)° . find the value of x
Answers
Answered by
96
As we know that pentagon have 540°
then
(x-5)+(x-6)+(2x-7)+x+(2x-2)=540°
7x-20=540°
7x=540+20
7x=560
x=560/7
x=80°
then
(x-5)+(x-6)+(2x-7)+x+(2x-2)=540°
7x-20=540°
7x=540+20
7x=560
x=560/7
x=80°
Answered by
62
As we know ,
Sum of angles of a Pentagon = 540°
Therefore :
(x - 5)° + ( x-6)° + ( 2x -7)° + ( x)°+(2x - 2)° = 540°
7x - 20° = 540°
7x = 540° + 20°
7x = 560°
x = 560/7
=> 80°
Ans . 80° is the value of x.
Sum of angles of a Pentagon = 540°
Therefore :
(x - 5)° + ( x-6)° + ( 2x -7)° + ( x)°+(2x - 2)° = 540°
7x - 20° = 540°
7x = 540° + 20°
7x = 560°
x = 560/7
=> 80°
Ans . 80° is the value of x.
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