Question

the measure of angles of a traingles are x,(x-40),(x-50).find the measure of each angle.

(please do in step by step and these question is of 9th standard)​

Answer 1

Answer:

We know that sum of all angle of triangle is 180°

x+x- 40° + x -50° = 180°

3x - 90° = 180°

3x = 180° + 90°

3x = 270°

x = 270°/3

x = 90°

First angle = 90°

Second angle = x - 40° = 90° - 40° = 50°

Third angle = x - 50° = 90° - 50° = 40°

Answer 2

Given:-

• 1st Angle of the triangle = x°
• 2nd angle of the triangle = (x-40)°
• 3rd angle of the triangle = (x-50)°

To find:-

• Measure of each angle

Solution:-

According to Angle sum property of a triangle,

=$\sf{x^{\circ} + (x-40)^{\circ}+ (x-50)^{\circ} = 180^{\circ}}$

=> $\sf{ x + x - 40^{\circ} + x - 50^{\circ} = 180^{\circ}}$

=>$\sf{3x - 90^{\circ} = 180^{\circ}}$

=>$\sf{3x = 180^{\circ}+90^{\circ}}$

=>$\sf{3x = 270^{\circ}}$

=>$\sf{x = \dfrac{270^{\circ}}{3}}$

=>$\sf{x = 90^{\circ}}$

Measure of angles of the triangle:-

1st angle = x = 90°

2nd angle = (x-40)° = (90-40)° = 50°

3rd angle = (x-50)° = (90-50)° = 40°

Important Question:-

What is angle-sum property of a triangle?

Answer:- Angle-sum property of a triangle states that the sum of all the angles of a triangle is always 180°.