Question

The measure of angles of a triangle are x (x-20),(x-40) find the measure of eash angle

Answer 1

Answer:

Sum of angles in a triangle = (n-2)× 180° where n is the number of side

Number of sides in a triangle = 3

Sum of interior angles=( 3-2)× 180° = 180°

Given that,

1st angle = x°

2nd angle (x - 20)°

3rd angle = (x-40)°

So, an equation will be formed

x° + x° - 20° + x° - 40° = 180°

regrouping the terms in LHS ,

we have,

x° + x° + x° - 20° - 40° = 180°

3x° - 60° = 180°

3x = 180° + 60°

3x = 240°

x = \frac{240}{3}x=

3

240

x = 80

So,

1st angle = x = 80°

2nd angle = x -20° = 80° - 20° = 60°

3rd angle = x - 40° = 80° - 40° = 40°

Thus,

the angles of the given triangle 80° , 60° and 40°

Answer 2

Answer:

Step-by-step explanation:

by angle sum property

x + ( x - 20) + ( x - 40) = 180°

x + x + x - 20 - 40 = 180 °

3x - 60 = 180

3x = 180 + 60

3x = 240

x = 240/3

x = 80

therefore , measure of first angle = x = 80°

measure of second angle = x - 20 = 60°

measure of third angle = x- 40 = 40°