Question

The measure of angles of each a
traingle
X°(X-20) '(X-48degree) Find the measure of
each angle​

Answer 1

Answer:

Sum of angles in a triangle = (n-2)× 180° where n is the number of side

Number of sides in a triangle = 3

Sum of interior angles=( 3-2)× 180° = 180°

Given that,

1st angle = x°

2nd angle (x - 20)°

3rd angle = (x-40)°

So, an equation will be formed

x° + x° - 20° + x° - 40° = 180°

regrouping the terms in LHS ,

we have,

x° + x° + x° - 20° - 40° = 180°

3x° - 60° = 180°

3x = 180° + 60°

3x = 240°

x = \frac{240}{3}x=

3

240

x = 80

So,

1st angle = x = 80°

2nd angle = x -20° = 80° - 20° = 60°

3rd angle = x - 40° = 80° - 40° = 40°

Thus,

the angles of the given triangle 80° , 60° and 40°

Answer 2

Step-by-step explanation:

Let x be the exterior angle (in degrees).

Then the exterior angle is equal to the sum of the two non-adjacent interior angles.

x+45=180 (sum of adjacent angles forming a straight line)

x=180−45=135 degree ⇒ exterior angle.

Interior angle: sum of the angles inside =180

The 2 base angles of an isosceles triangle are equal, so we'll represent each as z.

z+z+45=180

2z=180−45

2z=135

z=67.5 degree ⇒ interior angle.

So, interior angle =67.5 degree, exterior angle =135 degree.