the measure of each interior angle of a regular polygon is 140 then find the no of its side
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Sum of all interior angles of polygon = (n-2) × 180°
140°×n = ( n-2 )× 180°
140n = 180n - 360
360 = 180n - 140n
360 = 40 n
n = 360/ 40
n = 9
Hence the no. of sides of polygon is 9
140°×n = ( n-2 )× 180°
140n = 180n - 360
360 = 180n - 140n
360 = 40 n
n = 360/ 40
n = 9
Hence the no. of sides of polygon is 9
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