Question

the measure of hypotenuse of a isosceles right angle triangle is 8√9,what is the measure of its equal side​

Answer 1

Answer

• The measure of it's equal sides = 12√2.

Given

• The measure of hypotenuse of a isosceles right angle triangle = 8√9 units.

To Find

• The measure of it's equal sides.

Step By Step Explanation

Assumption :

Let us consider the measure of equal sides be x.

By using Pythagoras Theorum :

(Hypotenuse)² = (Perpendicular)² + (Base)². ★

By substituting the values :

Let's substitute the values in the above formula to find the measure of equal sides.

$\longmapsto \sf {(8 \sqrt{9}) }^{2} = {x}^{2} + {x}^{2} \\ \\ \longmapsto \sf 64 \times 9 = 2 {x}^{2} \\ \\ \longmapsto \sf 576 = 2 {x}^{2} \\ \\ \longmapsto \sf \cancel\cfrac{576}{2} = {x}^{2} \\ \\ \longmapsto \sf 288 = {x}^{2} \\ \\ \longmapsto \sf \sqrt{288} = x \\ \\ \longmapsto \underline {\boxed{\bold{ \green{12 \sqrt{2} \: \: units = x}}}}\:\:\:\:\red\bigstar$

Therefore, the measure of it's equal sides = 12√2 units.

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