Question

the measure of one angle of a parallelogram is 65°.find the measure of each remaining three angles​

Answer 1

measure of remaining three angles are 115°,65° and 115°

Answer 2

Answer:

LET ANGLES BE A, B, C AND D (WHERE A AND C ARE OPP. ANGLES AND B AND D ARE OPPOSITE TO EACH OTHER

LET A BE 65°

THEREFORE, C = 65°

ACC. TO ANGLE SUM PROPERTY OF QUADRILATERAL

A+B+C+D = 360°

65+65+B+D= 360°

→ 2B = 360°-130 (BECAUSE B AND D ARE OPPOSITE ANGLES...AND THUS ARE EQUAL)

→B = 230/2

→B = 115°

AND, D= 115°