The measure of one angle of a parallelogram is 80 degree what are the measure of the remaining angles
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Answered by
71
Let the parallelogram be ABCD and angle A be 80°
Angle A + angle B = 180° (alternate angles of a parallelogram are supplementary)
80+ angle B = 180
Angle B = 180-80 = 100
Angle C = angle A (interior opposite angles of a parallelogram are equal)
Angle C = 80°
Angle D = angle B (interior opposite angles of a parallelogram are equal)
Angle D = 100°
Angle A + angle B = 180° (alternate angles of a parallelogram are supplementary)
80+ angle B = 180
Angle B = 180-80 = 100
Angle C = angle A (interior opposite angles of a parallelogram are equal)
Angle C = 80°
Angle D = angle B (interior opposite angles of a parallelogram are equal)
Angle D = 100°
Answered by
24
angle A +angle B = 180°
therefore , 80+angle B =180° (sum of adjacent angles of //gm )
angle B =180 - 80
=100 °
therefore angle B =100°
also, angle C=angle A ( opp. angles of //gm are equal)
angle C =80°
angle B =angle D (opp. angles of //gm is equal)
therefore angle D = 100°
therefore , 80+angle B =180° (sum of adjacent angles of //gm )
angle B =180 - 80
=100 °
therefore angle B =100°
also, angle C=angle A ( opp. angles of //gm are equal)
angle C =80°
angle B =angle D (opp. angles of //gm is equal)
therefore angle D = 100°
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