Question

The measure of one side of a right triangular field is 4.2m.If the difference of the lengths of hypotenuse and the other side is 14m, find the sides of the triangle and its area.

Answer 1

Let the perpedicular, p=4.2 m and base is b m, hypotenuse is h m.
Then by the given question, h-b=14⇒h=b+14
Then by Pythagoros's theorem,
p²+b²=h²
or, (4.2)²+b²=(b+14)²
or, 17.64+b²=b²+2.b.14+196
or, 17.64=28b+196
or, 28b=-178.36
or, b=-178.36/28
or, b=-6.37
Since any side of a triangle can't be negative that means the datas given are wrong.

Answer 2

Let the perpedicular, p=4.2 m and base is b m, hypotenuse is h m.

Then by the given question, h-b=14⇒h=b+14

Then by Pythagoros's theorem,

p²+b²=h²

or, (4.2)²+b²=(b+14)²

or, 17.64+b²=b²+2.b.14+196

or, 17.64=28b+196

or, 28b=-178.36

or, b=-178.36/28

or, b=-6.37

Since any side of a triangle can't be negative that means the datas given are wrong.

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