The measure of the acute angle of an isosceles right angled triangle is
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the answer is 45 degree
since its a right angled isosceles triangle we can take the angles as x,x,90.because the base angles will be equal
therefore
x+x+90= 180( sum of 3 angles is 180)
2x=90
x= 45
Answered by
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Here is your solution
Given :-
ABC is a right isosceles Triangle .
in which
Two sides are equal
I. e
AC = BC
hence
∠A=∠B
∠ACB = 90°
we know that
sum of triangle is 180°
∠A+∠B+∠c = 180
∠A+∠B+90° = 180
∠A+∠A+90° = 180° [ ∠A = ∠B Given ]
2∠A+90° = 180°
2∠A = 180°-90°
∠A = 90°/2
∠A=45°
Hence
measure of acute angle of a right angled isosceles triangle is 45°
Hope it helps you
Given :-
ABC is a right isosceles Triangle .
in which
Two sides are equal
I. e
AC = BC
hence
∠A=∠B
∠ACB = 90°
we know that
sum of triangle is 180°
∠A+∠B+∠c = 180
∠A+∠B+90° = 180
∠A+∠A+90° = 180° [ ∠A = ∠B Given ]
2∠A+90° = 180°
2∠A = 180°-90°
∠A = 90°/2
∠A=45°
Hence
measure of acute angle of a right angled isosceles triangle is 45°
Hope it helps you
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