Question

The measure of the angles of a pentagon are (x - 5)º, (x – 6)°, (2x - 7)º, x° & (2x - 2)°​

Answer 1

Answer:

Sum of interior angles = (n-2)180

                                     =(5-2)180

                                     =3 x 180

                                     = 540°​

so,

x-5 + x-6 + 2x-7 + x  + 2x-2 = 540°​

7x + (-20) = 540°​

7x=540+20

7x=560°​

x=560/7=80°​

Interior angles =

x-5

= 80-5

=75°​

x-6

=80-6

=74°​

2x-7

=(2x80)-7

=160-7

=153°​

x=80°​

2x-2

=(80x2)-2

=160-2

=158°​

Hope my answer is helpful.