Question

the measure of the angles of a quadrilateral are (3x+15)°,(x+20)°,(2x+30)°,(3x-20)° then,x=? ​

Answer 1

Step-by-step explanation:

Since the sum of the angles of a quadrilateral is 360

Since the sum of the angles of a quadrilateral is 360 0

Since the sum of the angles of a quadrilateral is 360 0

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x=

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10380

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10380

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10380 =38

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10380 =38Now, x=38⇒2x=2×38=76

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10380 =38Now, x=38⇒2x=2×38=763x−40=3×38−40=74

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10380 =38Now, x=38⇒2x=2×38=763x−40=3×38−40=74and 4x+20=4×38+20=172

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10380 =38Now, x=38⇒2x=2×38=763x−40=3×38−40=74and 4x+20=4×38+20=172Thus, the measures of the angles are 38

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10380 =38Now, x=38⇒2x=2×38=763x−40=3×38−40=74and 4x+20=4×38+20=172Thus, the measures of the angles are 38 0

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10380 =38Now, x=38⇒2x=2×38=763x−40=3×38−40=74and 4x+20=4×38+20=172Thus, the measures of the angles are 38 0 ,74

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10380 =38Now, x=38⇒2x=2×38=763x−40=3×38−40=74and 4x+20=4×38+20=172Thus, the measures of the angles are 38 0 ,74 0

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10380 =38Now, x=38⇒2x=2×38=763x−40=3×38−40=74and 4x+20=4×38+20=172Thus, the measures of the angles are 38 0 ,74 0 ,76

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10380 =38Now, x=38⇒2x=2×38=763x−40=3×38−40=74and 4x+20=4×38+20=172Thus, the measures of the angles are 38 0 ,74 0 ,76 0

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10380 =38Now, x=38⇒2x=2×38=763x−40=3×38−40=74and 4x+20=4×38+20=172Thus, the measures of the angles are 38 0 ,74 0 ,76 0 and 172

Since the sum of the angles of a quadrilateral is 360 0 Therefore, x+(3x−40)+2x+(4x+20)=360 0 ⇒10x−20=360 0 ⇒10x=360+20=380⇒x= 10380 =38Now, x=38⇒2x=2×38=763x−40=3×38−40=74and 4x+20=4×38+20=172Thus, the measures of the angles are 38 0 ,74 0 ,76 0 and 172 0

Answer 2

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Step-by-step explanation:

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