Question

The measure of the angles of a triangle are in A.P and the greatest is 5 times the smallest (least). Find the angles in radian and degree.

Answer 1

let's the measures of angles be a-d,a,a+d

a-d+a+a+d=180°

3a=180°

a=60°

according to given conditions,

greater angle=a+d

a+d=5(a-d)

a+d=5a-5d

6d=4a=4×60=240

d=240÷6

d=40°

therefore, the measures of angle are 20°,60°,100°

In radian,

$20 \times \pi \div 180 = \pi \div 9$

$60 \times \pi \div 180 = \pi \div 3$

$100 \times \pi \div 180 = 5\pi \div 9$

hope that it will help you,

THANK YOU...