Question

the measure of the angles of the triangle abc are x°, (x-20)°, (x-40)°, find measure of each angle



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Answer 1

Answer:

sum of angles of triangle is = 180°

so, x + ( x - 20° ) + ( x - 40° ) = 180°

3x - 60° = 180°

X = 80°

hence, angles are 80° , 60° , 40°

Answer 2

Given: The measure of the angles of the ∆ABC are x°, (x – 20)°, (x – 40)°.

Need to find: The measure of each angle.

❍ Let the angles of the given Triangle be A, B and C respectively.

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$\underline{\bf{\dag} \:\mathfrak{As\;we\;know\: that\: :}}$⠀⠀⠀⠀

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• Sum of all angles of the triangle is 180°.

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Therefore,

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$\implies\sf x^\circ + (x - 20)^\circ + (x - 40)^\circ = 180^\circ\\\\\\:\implies\sf 3x - 60^\circ = 180^\circ\\\\\\:\implies\sf 3x = 180^\circ + 60^\circ \\\\\\:\implies\sf 3x = 240^\circ\\\\\\:\implies\sf x = \cancel\dfrac{240^\circ}{3}\\\\\\:\implies{\underline{\boxed{\frak{\pink{x = 80^\circ}}}}}\;\bigstar$

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Hence,

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• First angle, x = 80°.
• Second angle (x - 20), (80 - 20) = 60°.
• Third angle (x - 40), (80 - 40) = 40°.

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$\therefore{\underline{\sf{Hence, \; measure\;of\;each\;angle\;is\;\bf{80^\circ,60^\circ\;\&\;40^\circ}.}}}$

$\rule{300}2$