Question

The measure of the diagonal of a rectangle is 5 cm,If one of its sides is 3 cm then find its perimeter.

Answer 1

Answer:

Using the formulas

P=2(l+w)

d=w2+l2

Solving forP

P=2l+2d2﹣l2=2·3+2·52﹣32=14cm

Answer 2

Answer:

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Step-by-step explanation:

In rectangle ABCD

AC=5cm

AD=3cm

by pythagoras theorem

h²=p²+b²

5²=3²+b²

25=9+b²

25‐9=b²

16=b²

4=b

therefore,CD=4cm

Again,AB=DC and AD=BC

perimeter of rectangle=2(l+b)

=2(4+3)m

=(2×7)m

=14m