Question

The measure of the length of a chord of a circle is 16cm and its distance from the centre of the circle is 6cm.the radius of circle is

Answer 1

$( {h})^{2} = ( {8})^{2} + ({6})^{2} \\ ( {h})^{2} = 64 + 36 \\ ( {h})^{2} = 100 \\ h \: = 10cm.$

hence radius is 10cm.

Answer 2

Step-by-step explanation:

The perpendicular drawn from the centre of circle bisects the chord.

Here it forms a right angled triangle since distance between centre of circle and chord is perpendicular to chord.

By pythagorus theorem.

Radius(r)^2=8^2+6^2

=64+36=100

(on taking square root of both sides)

Radius=10 cm.

The radius of circle is 10cm.