Math, asked by dmshinde1977, 2 months ago

The measure of the side of a wall of a square room if 12 m. Find the cost of covering the wall with a wall paper at the rate of rupees 40 per sq m.

(::please explain it::) ​

Answers

Answered by TumhaariMaut
6

Answer

Let h be the height.

Rate of covering the floor with mat = Rs 25 per square metre

Total cost for floor = RS 2700

Area of the floor = (total cost)/ (cost per meter) 

Area of the floor =252700=108m2 

Breadth = (area of the floor) / Length =12108 = 9m

Length of a wall = 12 m

Rate  of painting the four walls of a room = Rs 30 per square metre

Total cost = RS 7560

Again,

Area of walls = (total cost)/ (cost per meter) =7560/30=252m2

Now,

Area of 4 walls = 2(Length of walls × Height of walls) + 2(Breadth of walls × Height of walls)

252=2(12×h)+2(9×h)

252=24h+18h

252=42h

h=6

⇒ Height is 6 m

Therefore dimensions of the room are :12m×9m×6m

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Answered by Anonymous
5

QUESTION ↘️

The measure of the side of a wall of a square room if 12 m. Find the cost of covering the wall with a wall paper at the rate of rupees 40 per sq m.

ANSWER ↘️

To find the cost of covering the wall, we need to find its area.

So,

Area of the square wall << (side) x (side)

Area of the square wall << (12) x (12)

Area of the square wall << 144 cm.^2

Now,

Cost of covering it with a wallpaper << 144 x 40

Cost of covering it with a wallpaper << Rs.5760

Answer << Rs.5760

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