Question

the measure of the two adjacent angle of a parallelogram are the ratio 4:5. find the measure of the each angle of the parallelogram​

Answer 1

see the attachment and plzz mark me as brainliest...plzz dear

Answer 2

$\huge\sf\pink{Answer}$

☞ Angles = 80°,80°,100° and 100°

$\rule{110}1$

$\huge\sf\blue{Given}$

✭ Two Adjacent sides of a parallelogram are in ratio of 4:5

$\rule{110}1$

$\huge\sf\gray{To \:Find}$

➢ Measure of each angle of parallelogram

$\rule{110}1$

$\huge\sf\purple{Steps}$

We are know that,

❍ The adjacent sides of parallelogram are in ratio of 4:5.

◕ Let, the angles be 4x and 5x

Also, we know that the opposite angles of parallelogram are equal. So, we can say that the measure of angles of parallelogram will be equal to 360° , by angle sum property of Quadrilateral.

So, the angles are, 4x, 5x, 4x and 5x

Now, by angle sum property of the quadrilateral

➳ 4x + 5x + 4x + 5x = 360°

➳ 9x + 9x = 360°

➳ 18x = 360°

➳ x = 360/18

➳ $\sf\orange{x = 20}$

$\rule{110}1$

✪ Now,the measure of all the angles of parallelogram are,

• $\sf\red{ 4x = 4(20)} = \green{80^°}$

• $\sf\red{5x = 5(20) }= \green{ 100^°}$

$\rule{170}3$