the measure of two abjacent angles of parallelogram are in the ratio of 4:5 find the measure of each of the parallelogram
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Let ∠A and ∠B are two adjacent angles.
But we know that sum of adjacent angles of a parallelogram is 180°
∠A+∠B=180°
Given that adjacent angles of a parallelogram are in the ratio 4:5 and let that ratio be multiple of x
∠A+∠B=180°
4x+5x=180°
9x=180°
x=180/9
x=20°
∠A=4x=4×20=80°
∠B=5x=5×20=100°
Also ∠B+∠C=180°
[Since ∠B and ∠C are adjacent angles]
100°+∠C=180°
∠C=180°−100°
=80°
Now, ∠C+∠D=180°
[Since ∠C and∠D are adjacent angles]
80°+∠D=180°
∠D=180°−80°
=100°
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