Question

The measure of two adjacent angle of a parallelogram are in ratios 3:2. Find the measure of each of the angles of the parallelogram.

Answer 1

let the two adjacent angle be 3x and 2x
a/q
3x+2x=180
5x=180
x=180/5
x =36
angle a=3x=3×36=108
angle b =2x=2×36=72
angle c =108
angle d= 72
please give me branliest mark

Answer 2

Answer:

Let ∠A = 3x and ∠B = 2x

∠A + ∠B = 180

(Adjacent angle : Supplementary)

3y + 2x ⇒ 5x = 180 ⇒ x = 180 /5

x = 36 ∘

∠A = ∠C = 3x = 3 × 36

= 108 ∘

∠B = ∠D = 2x = 2 × 36 = 72 ∘