Question

the measure of two adjacent angles of a parallelogram are in ratio 3:2 find the measure of each of the angles of a parallelogram​

Answer 1

Answer:

let the angles be 3x° and 2x°

a/q,3x°+2x°=180

x=180/5=36°

3x=3×36=108

2x=2×36=72

Answer 2

Answer:

Let the measures of two adjacent angles, ∠A and ∠B, of parallelogram ABCD are in the ratio of 3:2.

Let ∠A = 3x and ∠B = 2x

We know that the sum of the measures of adjacent angles is 180º for a parallelogram.

∠A + ∠B = 180º

3x + 2x = 180º

5x = 180º

∠A = ∠C = 3x = 108º (Opposite angles)

∠B = ∠D = 2x = 72º (Opposite angles)

Thus, the measures of the angles of the parallelogram are 108º, 72º, 108º, and 72º.