The measure of two adjacent sides of a rectangle are in the ratio of 11:10.If the perimeter of the rectangle is 84 cm,find its area?
Answers
Answered by
16
Hi there✋✋,
Here's the answer:-
Let the sides be 11x and 10x
Perimeter = 2(11x + 10x) = 2(21x) = 42x
=> 42x = 84
=> x = 2
So,
The sides are 22 and 20 respectively.
Area = l×b = 22× 20 cm² = 440cm²
HOPE IT HELPS ☺
PLEASE MARK BRAINLIEST
Here's the answer:-
Let the sides be 11x and 10x
Perimeter = 2(11x + 10x) = 2(21x) = 42x
=> 42x = 84
=> x = 2
So,
The sides are 22 and 20 respectively.
Area = l×b = 22× 20 cm² = 440cm²
HOPE IT HELPS ☺
PLEASE MARK BRAINLIEST
Answered by
6
Let the two adjacent sides are 11x&10x.
Perimeter =2 (11x+10x)
=2×21x
=42x
Perimeter =84cm (given )
42x=84
x=2cm
so,Length =11×2=22cm Breadth =10×2=20cm
Therefore, Area=Length ×Breadth
= 22×20=440cm^2
Perimeter =2 (11x+10x)
=2×21x
=42x
Perimeter =84cm (given )
42x=84
x=2cm
so,Length =11×2=22cm Breadth =10×2=20cm
Therefore, Area=Length ×Breadth
= 22×20=440cm^2
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