the measure of two adjacent sides of a rectangle are in the ratio 11 : 10 if the area is 3960 m square then find its length and breadth
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Answered by
33
Let the common ratio be x.so sides are
11x and 10 x .
now area of rectangle=l×b=11x×10x=110x^2
now 110x^2=3960
x^2=3960÷110=36
x=6
11x=11×6=66
10x=10×6=6660
length of rectangle =66m
breadth of rectangle =60m
11x and 10 x .
now area of rectangle=l×b=11x×10x=110x^2
now 110x^2=3960
x^2=3960÷110=36
x=6
11x=11×6=66
10x=10×6=6660
length of rectangle =66m
breadth of rectangle =60m
Answered by
8
Answer:
Hope it's helpful to you
Step-by-step explanation:
The common ratio = ×
=11× and 10×
Area of rectangle = l×b =11× multiply 10×
=110 × 2
110 ×2 = 3960
×2=3960÷110
=36
×=6
11×=11×6=66
10×10×6=6660
Length of rectangle =66 m
Breadth of rectangle =60 m
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