Question

the measure of two adjacent sides of a rectangle are in the ratio of 11:10. If the perimeter of the rectangle is 84 CM, find its area​

Answer 1

        $\text{It is given that two adjacent sides of a rectangle are in the ratio }11:10$

        $\text{Let the common ratio be }x$

$\implies \: \text{The two sides are }11x \text{ and }10x$

        $\text{We know that perimeter of a rectangle} = 2(\text{sum of two adjacent sides})$

        $\text{Also, perimeter of rectangle is }84 \; cm \; \; \; \; \; \; (\text{Given})$

$\implies \: 84 = 2(11x + 10x)$

$\implies \: 84 = 2(21x)$

$\implies \: 84 = 42x$

$\implies \: x = 2$

$\implies \: \boxed{\text{The two sides are }11x = 11(2) = 22 \; cm \; \; ; \; \; 10(x) = 10(2) = 20 \; cm}$

Answer 2

parameter = 84 cm

X is given below

84= 2x(11x + 10x)

84/2 = 11x + 10x

42/21 = X

X = 2