Question

The measure of two adjancent angles of a parallelogram are in the ratio of 3:2 find the measure of each parallelogram​

Answer 1

Answer:

108°, 72° , 108° and 72°

Step-by-step explanation:

Let the 1st angle be '3x'. 2nd angle must be 2x.

Moreover, other two angles must be same as 1st and 2nd angles respectively.

Sum of all interior angles of quadrilateral is 360°

⇒ 3x + 2x + 3x + 2x = 360

⇒ 3x + 2x + 3x + 2x = 360

⇒ 10x= 360

⇒ x = 360)/10

⇒ x = 36°

    ∴required angles are:

3x = 3(36)° = 108°    &

2x = 2(36)° = 72°

Other two are same as of 108° and 72°.

Answer 2

Question:-

• The measure of two adjacent angles of a parallelogram are in the ratio of 3:2 find the measure of each parallelogram.

To Find:-

• Find the measure of each parallelogram.

Solution:-

• Let the first angle be ' 3x '

• Second angle be ' 2x '

As we know that:-

• Sum of interior angles is 360°

$\longrightarrow\sf \: 3x + 2x + 3x + 2x = 360$

$\longrightarrow\sf \: 10x = 360$

$\longrightarrow\sf \: x = \cancel\dfrac { 360 } { 10 }$

$\longrightarrow\sf \: x = 36$

Hence ,

• First angle is 3x = 108°

• Second angle is 2x = 72°