The measure of two adjucent angles of a parallelogram are in the ratio 3:2 find the measure of each of the angles of the parallelogram.
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Answer:
ABCD be 3x and 2x respectively.
Since the adjacent angles of a parallelogram are supplementary.
∠A+∠B=180
o
⇒3x+2x=180
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⇒5x=180
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⇒x=
5
180
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=36
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∴∠3×36
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=108
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and, ∠B=2×36
o
=72
o
Since the opposite angles are equal in a parallelgram, therefore, ∠C=∠A=108
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and ∠D=∠B=72
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Hence, ∠A=108
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,∠B=72
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,∠C=108
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and ∠D=72
o
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