Question

The measure of two opposite angles of a parallelogram are (3x-5) and (x-50) find all angles of parallelogram​

Answer 1

Answer:-

102.5°, 77.5°, 102.5°, 77.5°.

Step-by-step explanation:

Given:-

• Measure of opposite angles of parallelogram are 3x-5, x+50
• Correction ☑ 50 will be positive that is the angles will be 3x-5, x+50.

Solⁿ

=> we know that opposite angles of parallelogram are equal

=> 3x-5= x+50

=> 3x-x= 55

=> 2x=55

=> x = 27.5

Since 3x-5=x+50 Therefore x+50 = 27.5°+50°=77.5°

=>So Value of Angle adjacent to 77.5° = 180-77.5°

As Sum of adjacent angles is equal to 180°

=>Therefore Value of angle adjacent to 77.5°=102.5°

=>As opposite angles are equal so angle opposite to 102.5° = 102.5°

Therefore All angles of Parallelogram are 102.5°,77.5°,102.5°,77.5°

I hope It Helps You!!!!.... :):)