Question

the measure of two parallel side of a Trapezium are 24cm and 38cm and distance between then is 48 cm find the area of Trapezium​

Answer 1

Answer:

answer is 1488cm sq..

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Answer 2

$\fbox{\texttt{\green{Answer:}}}$

Area of trapezium = 1488 cm²

$\fbox{\texttt{\pink{Given:}}}$

• Length of parallel side (AB) = 24 cm
• Length of parallel side (CD) = 38 cm
• Distance between parallel sides (AF) = 48 cm

$\fbox{\texttt{\blue{To\:find:}}}$

Area of the trapezium(ABCD).

$\fbox{\texttt{\red{How\:to\:Find:}}}$

Formula for finding area of trapezium =

$\bold{\frac{1}{2}\times{}(a+b)h}$

(Here, a & b stands for the two Ⅱ sides & h stands for the diatance between the Ⅱ sides)

$\hrulefill$

Applying the formula for the given trapezium, we get,

$\implies\bold{Ar(ABCD)=\frac{1}{2}(AB+CD)AF}$

$\implies\bold{Ar(ABCD)=\frac{1}{2}(24+38)48}$

$\implies\bold{Ar(ABCD)=\frac{1}{2}\times{}62\times{}48}$

$\implies\bold{Ar(ABCD)=\frac{1}{2}\times{}2976}$

$\implies\bold{Ar(ABCD)=\frac{2976}{2}=1488\:cm^2}$

∴ Area of trapezium = 1488 cm²