the measured emf at 25°C for the cell reaction. Zn + Cu2+(1.0M) gives Cu + Zn 2+(0.1M) is 1.3 volt calculate E° for the cell
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Given :
Emf of cell reaction (E) = 1.3 V
To find :
E° for the cell =?
Solution:
- By using Nernst equation
Ecell = E°cell - (0.0591/2)×log(I zn²⁺ I / I cu²⁺ I)
- By substituting the values in above equation
- 1.3 = E°cell - (0.0591/2)×log( 0.1/1)
- 1.3 = E°cell +0.02955×log(10)
- E°cell = 1.3 - 0.2955
- E°cell = 1.27 V
E° for the cell is 1.27V
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