The measured, length and breadth of a rectangle are (5.32+- 0.01).cm and (4.98 +- 0.01 cm respectively. calculate the area of rectangle with error limits .help me
Answers
Answered by
0
Explanation:
The thickness of cylinder wall with the error limits is equal to 0.34 +- 0.02.
The solution is as follow:
Internal diameter= 3.89+0.01 cm
Vol 79
106
3.0
External diameter=4.23+0.01 cm
Thickness (t) = External- Internal
Therefore, t= 4.23-3.89= 0.34
Hence, thickness of cylinder wall with the error limits is equal to 0.34 plus minus 0.02 (0.01+0.01)
Similar questions