Question

The measured length of two rods are li = 30
cm + 0.5 cm and l2 = 20 cm + 0.1 cm. The
percentage error in difference of length of
rods is
​

Answer 1

Answer: The percentage error is 4%.

Explanation:

L1 = 30 cm + 0.5cm; (ΔL1 = 0.5)

L2 = 20 cm + 0.1 cm; (ΔL2 = 0.1)

Difference of length in rods = L1 - L2

                                              = (30 cm - 20 cm) ± (0.5-0.1)

                                              = 10 cm ± 0.4 cm

Percentage error = |Accepted value - Experimental value| / Accepted value

                             = 0.4 / 10 x 100

                             = 4%

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