Question

the measured length of tworods are l1=30cm+-0.5 cm and l2=20cm+-0.1cm.The percentage error in difference of length of rods is​

Answer 1

Answer:

10 cm is eeor diffecence between them

Answer 2

Explanation:

Given l

1

=1.8±0.2

And, l

2

=2.3±0.1

⇒l=l

1

+l

2

=4.1m

Since, error is additive in nature, Δl=Δl

1

+Δl

2

=0.3m

So, combined length with error limits is (4.1±0.3)m