The measured mass and diameter of a uniform brass ball are 29.150 x 10° kg and 1.92 x 10m
respectively. Express the density of brass in appropriate significant figures.
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Explanation:
given
mass=29.150×10^-3kg
diameter=1.92×10^-2m
radius=9.6×10^-3m
density,p=?
therefore
density,p=mass/volume
volume=4/3πr^3
=4/3×3.14×9.6×9.6×9.6×10^-3×10^-3×10^-3
=4.19×884.74×10^-9
=3707.06×10-9
now,
density,p=mass/volume
=29.150/3707.06×10^-9
=29.150×10^9/3707.06
=0.0078633×10^9
=7.8633×10^3
=7.86×10^3
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